Line Integral

Transcribed Lecture Notes (Complete)

1. Definition of Line Integral

A line integral is an integral where the function to be integrated is evaluated along a curve. There are two main types of line integrals we consider in vector calculus:

Scalar Field Line Integral

For a scalar field f(x,y,z)f(x, y, z) and a curve CC, the line integral is:

∫Cf(x,y,z) ds\int_C f(x, y, z) \, ds

Here, dsds represents an infinitesimal arc length along the curve CC. This computes the area of a "curtain" of height ff following the path CC.

Vector Field Line Integral

More common in physics is the line integral of a vector field F⃗(x,y,z)\vec{F}(x, y, z) along a curve CC. It is defined as:

∫CF⃗⋅dr⃗\int_C \vec{F} \cdot d\vec{r}

Where dr⃗d\vec{r} is an infinitesimal vector displacement along the path.

2. Physical Interpretation: Work Done

The most important physical interpretation of a vector line integral is the concept of mechanical work. The work done WW by a force field F⃗\vec{F} on a particle moving along a path CC is precisely the line integral of the force along that path.

W=∫CF⃗⋅dr⃗W = \int_C \vec{F} \cdot d\vec{r}

3. Evaluation using Parameterization

To compute a line integral, we typically parameterize the curve CC using a parameter tt. Let the curve be given by r⃗(t)=x(t)i^+y(t)j^+z(t)k^\vec{r}(t) = x(t)\hat{i} + y(t)\hat{j} + z(t)\hat{k}, for a≤t≤ba \leq t \leq b.

We can express the differential displacement as:

dr⃗=dr⃗dtdt=r⃗′(t)dtd\vec{r} = \frac{d\vec{r}}{dt} dt = \vec{r}'(t) dt

Then the line integral transforms into a standard single-variable integral over tt:

∫CF⃗⋅dr⃗=∫abF⃗(r⃗(t))⋅r⃗′(t) dt\int_C \vec{F} \cdot d\vec{r} = \int_a^b \vec{F}(\vec{r}(t)) \cdot \vec{r}'(t) \, dt

4. Conservative Fields & Path Independence

A vector field F⃗\vec{F} is called conservative if it can be expressed as the gradient of a scalar potential function ϕ(x,y,z)\phi(x, y, z):

F⃗=∇ϕ\vec{F} = \nabla \phi

Fundamental Theorem of Line Integrals

For a conservative field, the line integral is path-independent. It depends only on the start point AA and end point BB, not on the specific curve CC connecting them:

∫ABF⃗⋅dr⃗=∫AB(∇ϕ)⋅dr⃗=ϕ(B)−ϕ(A)\int_A^B \vec{F} \cdot d\vec{r} = \int_A^B (\nabla \phi) \cdot d\vec{r} = \phi(B) - \phi(A)

Closed Loop Integral

An immediate consequence is that the line integral of a conservative field around any closed loop is zero (since start and end points are the same, A=BA = B):

∮CF⃗⋅dr⃗=0\oint_C \vec{F} \cdot d\vec{r} = 0